memmove - copy bytes in memory with overlapping areas

Syntax	#include <string.h> void *memmove(void *s1, const void *s2, size_t n);
Description	memmove() copies the first n bytes of the memory area to which s2 points into the memory area pointed to by s1. memmove() first copies the n bytes to a temporary field that does not overlap memory areas s1 and s2 and then copies the bytes from that field to the memory area s1. s1 is a pointer to the memory area to which the bytes are be copied. s2 is a pointer to the memory area from which the first n bytes are to be copied. n is an integer value that specifies the number of bytes in s2 to be copied.
Return val.	Pointer to memory area s1
		if successful.
Notes	This function is suitable for processing character arrays, which, in contrast to strings, need not be terminated with the null byte (\0). memmove() also works with memory areas that overlap; memcpy(), by contrast, does not.
See also	memcpy(), string.h.